27=(-26x^2)+3.62x+30.18

Solution for 27=(-26x^2)+3.62x+30.18 equation:

27=(-26x^2)+3.62x+30.18

We move all terms to the left:

27-((-26x^2)+3.62x+30.18)=0


We calculate terms in parentheses: -((-26x^2)+3.62x+30.18), so:

(-26x^2)+3.62x+30.18

We get rid of parentheses

-26x^2+3.62x+30.18

Back to the equation:

-(-26x^2+3.62x+30.18)


We get rid of parentheses

26x^2-3.62x-30.18+27=0

We add all the numbers together, and all the variables

26x^2-3.62x-3.18=0

a = 26; b = -3.62; c = -3.18;
Δ = b2-4ac
Δ = -3.622-4·26·(-3.18)
Δ = 343.8244
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3.62)-\sqrt{343.8244}}{2*26}=\frac{3.62-\sqrt{343.8244}}{52}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3.62)+\sqrt{343.8244}}{2*26}=\frac{3.62+\sqrt{343.8244}}{52}
$